(2x+4)/(2x^2-8)

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Solution for (2x+4)/(2x^2-8) equation: 


D( x )

2*x^2-8 = 0

2*x^2-8 = 0

2*x^2-8 = 0

2*x^2 = 8 // : 2

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(2*x+4)/(2*x^2-8) = 0

2*x+4 = 0 // - 4

2*x = -4 // : 2

x = -4/2

x = -2

x in { -2} 

x belongs to the empty set

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